x^2-x+9=(x+2)(x+3)

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Solution for x^2-x+9=(x+2)(x+3) equation: 



x^2-x+9=(x+2)(x+3)

We move all terms to the left:

x^2-x+9-((x+2)(x+3))=0

We add all the numbers together, and all the variables

x^2-1x-((x+2)(x+3))+9=0

We multiply parentheses ..

x^2-((+x^2+3x+2x+6))-1x+9=0



We calculate terms in parentheses: -((+x^2+3x+2x+6)), so:

(+x^2+3x+2x+6)

We get rid of parentheses

x^2+3x+2x+6

We add all the numbers together, and all the variables

x^2+5x+6

Back to the equation:

-(x^2+5x+6)



We add all the numbers together, and all the variables

x^2-1x-(x^2+5x+6)+9=0

We get rid of parentheses

x^2-x^2-1x-5x-6+9=0

We add all the numbers together, and all the variables

-6x+3=0

We move all terms containing x to the left, all other terms to the right

-6x=-3

x=-3/-6

x=1/2

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